Maximum height = \( \frac{(10\sqrt{2})^2}{2 \times 9.8} = \frac{200}{19.6} \approx 10.2 \, \text{meters} \)

Sat, 02 May 2026 03:56:13 +0000

Maximum Height of a Projectile: Calculating the Peak ÃƒÂ¢Ã‚Â€Ã‚Â“ A Detailed Explanation When throwing a ball upward or analyzing any vertical motion projectile, understanding how high it can rise is essential. A classic physics formula helps us calculate the maximum height a projectile reaches under gravity. In this article, we explore how to compute maximum height using the equation: \[
\ ext{Maximum height} = rac{(10\sqrt{2})^2}{2 \ imes 9.8} pprox 10.2 \, \ ext{meters}
\] LetÃƒÂ¢Ã‚Â€Ã‚Â™s break down how this formula is derived, how it applies to real-world scenarios, and why this value matters for physics students, engineers, and enthusiasts alike.