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Home » So $a = -2$, $b = 4$ - RoadRUNNER Motorcycle Touring & Travel Magazine

So $a = -2$, $b = 4$ - RoadRUNNER Motorcycle Touring & Travel Magazine

📅 April 30, 2026 👤 scraface

Apr 30, 2026

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📌 e 0 $, contradiction. So the only consistent solution is $ a = 0 $, and $ b $ is arbitrary.

📌 However, if the problem implies the identity for all $ a $, its impossible. But if its for a specific $ a $, we cannot determine $ b $.

📌 Then $ b $ is not determined. But if we assume $ a

📌 e 0 $, no solution. But the question asks for $ b $, implying it exists.

📌 With $ a = 0 $, the equation becomes $ 0 = 0 $, true for any $ b $.

📌 Thus, $ b $ is not uniquely determined. But if we must give a value, the only consistent interpretation is that the equation forces $ a = 0 $, and $ b $ remains free.

📌 Therefore, the equation cannot hold for all $ a $, unless $ a = 0 $.

📌 But if its for a specific $ a $, $ b $ is not constrained.

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