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Home » \Rightarrow \cos\theta = \frac12 - RoadRUNNER Motorcycle Touring & Travel Magazine

\Rightarrow \cos\theta = \frac12 - RoadRUNNER Motorcycle Touring & Travel Magazine

📅 April 30, 2026 👤 scraface

Apr 30, 2026

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📌 f(y) &= 3(y^2 - 4y + 4) + 12y - 24 + 7 \\

📌 &= 3y^2 - 12y + 12 + 12y - 24 + 7 \\

📌 &= 3y^2 - 5

📌 Somit ist die Funktion \( f(y) = 3y^2 - 5 \). Nun sustituieren wir \( y = x^2 - 2 \), um \( f(x^2 - 2) \) zu finden:

📌 f(x^2 - 2) = 3(x^2 - 2)^2 - 5

📌 Expandieren und vereinfachen:

📌 f(x^2 - 2) &= 3(x^4 - 4x^2 + 4) - 5 \\

📌 &= 3x^4 - 12x^2 + 12 - 5 \\

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