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📅 May 1, 2026 👤 scraface

May 01, 2026

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2\sin(z) = 1 \quad \Rightarrow \quad \sin(z) = rac{1}{2}
The solutions to \(\sin(z) = rac{1}{2}\) within the range \(0^\circ \...
z = 30^\circ, \quad z = 150^\circ
Next, consider the case where \(\cos(z) = 0\):
\cos(z) = 0 \quad \Rightarrow \quad z = 90^\circ, \quad z = 270^\circ
We verify these solutions in the original equation:
For \(z = 90^\circ\), \(\sin(180^\circ) = 0\) and \(\cos(90^\circ) = 0...
For \(z = 270^\circ\), \(\sin(540^\circ) = 0\) and \(\cos(270^\circ) =...
Thus, the angles \(z \in [0^\circ, 360^\circ]\) that satisfy the equat...
z = 30^\circ, \quad 150^\circ, \quad 90^\circ, \quad 270^\circ

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