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📰 d(t) = t^3. 📰 But $ d(t) = t^3 $ is strictly convex and has no minimum (it decreases on $ (-\infty, 0) $, increases on $ (0, \infty) $), so it does not achieve a minimum. However, the problem states that the **minimum depth is achieved exactly once**, which implies $ d(t) $ has a unique global minimum. But $ t^3 $ has no such minimum. Contradiction? 📰 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions. 📰 List Of Characters From The Simpsons 📰 Nc Dmv Appointment 9907774 📰 Unlock Fast Transfers With Xoom Appmix Send And Receive In 715380 📰 Wells Fargo Credit Card Pre Approval 📰 Water Filters For Wells 2851559 📰 Banking Business Account 📰 Public Reaction Visibly Muscular Nyt That Changed Everything 📰 Youll Eyes Will Fly Open When You See The Once Impossible Blue Rose Finally Bloom 7282213 📰 They Said It Was Tinic But The Lover Test Proved Everythingabsolutely Jaw Dropping 3427748 📰 Zotero For Macbook 📰 Major Breakthrough Procurement And The Pressure Mounts 📰 Best High Def Antenna Indoor 📰 Firefighter Costume Reveal Trusted Looks That Look Like Real Heroes 9973447 📰 Delivery Slip 📰 S In Cursive Secrets That Scream When You Read 3128154