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May 01, 2026

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For $ x < 2 $, say $ x = 0 $: numerator $ -3(0) + 11 = 11 > 0 $, denom...
For $ 2 < x < rac{11}{3} $, say $ x = 3 $: numerator $ -9 + 11 = 2 >...
For $ x > rac{11}{3} $, say $ x = 4 $: numerator $ -12 + 11 = -1 < 0...
We want where the expression is **less than 0**, so the solution is wh...
x \in (-\infty, 2) \cup \left(rac{11}{3}, \infty
oxed{(-\infty, 2) \cup \left(rac{11}{3}, \infty
Question: Let $ a, b, c $ be real numbers such that $ a + b + c = 0 $....
Solution: We use the well-known algebraic identity:
a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca).
Given that $ a + b + c = 0 $, substitute into the identity:

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