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📅 May 2, 2026 👤 scraface

May 02, 2026

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e y\) (to avoid division by zero in the original expression).
Check that \(x = \sqrt{5} y\):
Then \( rac{x+y}{x-y} = rac{\sqrt{5}+1}{\sqrt{5}-1} = rac{3+\sqrt{5...
Similarly for \(x = -\sqrt{5} y\):
\( rac{-\sqrt{5}+1}{-\sqrt{5}-1} = rac{\sqrt{5}-1}{\sqrt{5}+1} = ra...
Therefore, the solutions are all real pairs where \( x = \sqrt{5} y \)...
e 0 \). However, since the equation is symmetric in \((x,y)\) under th...
oxed{(x, y) ext{ such that } x = \pm \sqrt{5} y, \; y
Question:** A historian analyzing a manuscript finds an expression inv...
ight| \), assuming \( w

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