Solution: This is a binomial probability problem with $ n = 4 $ trials (rolls), success probability $ p = \frac{1}{6} $ (rolling a 4), and we want exactly $ k = 2 $ successes.

Fri, 01 May 2026 03:56:36 +0000

# Solving a Binomial Probability Problem: Exactly 2 Successes in 4 Rolls with p = 1/6 If youÃƒÂ¢Ã‚Â€Ã‚Â™ve ever tossed a die and asked, ÃƒÂ¢Ã‚Â€Ã‚ÂœWhatÃƒÂ¢Ã‚Â€Ã‚Â™s the chance of rolling a 4 exactly twice in only 4 rolls?ÃƒÂ¢Ã‚Â€Ã‚Â ÃƒÂ¢Ã‚Â€Ã‚Â” youÃƒÂ¢Ã‚Â€Ã‚Â™re dealing with a classic binomial probability problem. In this article, we break down how to solve this using the binomial distribution formula, with $ n = 4 $, success probability $ p = rac{1}{6} $, and exactly $ k = 2 $ successes. --- ## What is a Binomial Probability Problem?